Lv1. 옹알이(2)

문제 보기 : 옹알이 (2)

프로그래머스

 

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문제

• 정답률 : 61%

 

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작성 코드

def solution(babbling):
    can = ["aya", "ye", "woo", "ma"]
    answer = 0
    # ans = []
    for word in babbling:
        # ans.append(word)
        aword = ""
        while True:
            if len(word)>=2 and word[0:2] in can and aword != word[0:2]:
                aword = word[0:2]
                word = word[2:]
            elif len(word)>=3 and word[0:3] in can and aword != word[0:3]:
                aword = word[0:3]
                word = word[3:]
            else:
                # ans = ans[:-1]
                break
                
            if len(word) == 0:
                answer += 1
                break
    return answer